
In Fig. 11.1, the apparent resistance seen at the primary terminals is


The answer is :- 4
The impedance ratio primary to secondary is the
same as the square of the turns ratio. Thus, for a turns ratio
of 20:1, the corresponding impedance ratio will be 400:1. Thus
the primary impedance will be 400 times that of the
secondary circuit, i.e. 1200![]()
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