If the circuit in Fig. 3.1 is connected across a
40V supply, the p.d. across the 10
resistor will be
The answer is :- 4
Total resistance = 20![]()
Total current = total p.d. / total resistance = 40 / 20 = 2 A
P.D. across 14
resistor = 2 x 14 = 28 V,
so p.d. across the parallel combination = 40 - 28 = 12 V,
i.e. the p.d. acrross both the 10
and 15
resistors.
| BACK |
| page (tq0306ex) |
| Some material Copyright John Bowyer G4KGS. |
| Click here for important Copyright information |
| Web Space provided by Hostroute.com Ltd |
| Contact details |