A moving coil instrument has an f.s.d. of 1mA.
When the instrument is connected to a 14.9k
multiplier it can read up to 15V. The
instrument resistance is



The answer is :- 2
In this question we must first ascertain how much
voltage is dropped across the multiplier and how much across
the meter. From Ohm's law, the voltage across the multiplier =
14900 x 0.001 = 14.9V. Thus only 0.1V is across the meter. From
Ohm's law (again) R=V/I = 0.1/0.001 = 100
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